如果x+2>5,那么x>3,根据是_______(不等式的基本性质3性质)

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/etc/nginx/nginx.conf.5.已知x&0,由不等式x+≥2,x2+≥3,x3+≥4,…,可以推广为(  )._答案_百度高考
5.已知x&0,由不等式x+≥2,x2+≥3,x3+≥4,…,可以推广为(  )._答案_百度高考
理科数学 不等式的性质...
5.已知x&0,由不等式x+≥2,x2+≥3,x3+≥4,…,可以推广为(  ).
Axn+≥n Bxn+≥n+1 Cxn+≥n+1 Dxn+≥n
考察知识点
不等式的性质
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第-1小题正确答案及相关解析用>或<填空,并说明是根据不等式的那一条性质: (1)若x+2>5,侧x用>或<填空,并说明是根据不等式的那一条性质:
(1)若x+2>5,侧x
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>根据:不等式两边减去同一个数,不等式仍成立
>性质是,不等式两边同减去一个数,不等式仍成立
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