f(x)=(x²-1)^n f^(n+1)(-1)=? 当x=-1时 f(x)的n+1cosx的n阶导数数

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已知函数f(x)=-3(x-m)²+ 2m²当x∈[2,3]y有最大值8求m的值
匿名 已知函数f(x)=-3(x-m)²+ 2m²当x∈[2,3]y有最大值8求m的值
因为函数开口向下,所以在对称轴的地方取到最大值,又因为最大值等于8,所以当X=2,M=2时担穿曹费丨渡查杀肠辑,Y有最大值8
x=m时f(x)取最大值,此时2m^2=8.所以m=2f(x)=(1+x/2)²–2,当x>=时,解方程f(x)=f^–1(x)
Kyoya恭OX3
哦,错了,是—2
显然f(x)在x>=-2递增
所以f(x)=f^–1(x)即f[f(x)]=x和f(x)=x同解
所以(1+x/2)^2-2=x
解得x=-2,x=2
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