810 ()根号2等于多少810(45X几)

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问题:阶地是在地壳垂直运动的影响下,由河流下切侵蚀作用而形成,有几...
问题详情 : 阶地是在地壳垂直运动的影响下,由河流下切侵蚀作用而形成,有几级阶地,就对应有几次地壳运动。图8示意某河流阶地的地形,其中等高距为10 m。某地质考察队沿剖面线在①②③④⑤处分别钻孔至地下同一水平面,利用样本分析得知①⑤为同一岩层且岩层年龄较新,②④为同一岩层且岩层年龄较老。读图完成下列问题。【小题1】图示地区的地质地貌为(&&&)A.背斜谷B.背斜山C.向斜谷D.向斜山【小题2】图中①②③④所在阶地形成年代最晚的是(&&)A.①B.②C.③D.④【小题3】若在②处钻30m到达采集样本水平面,则在⑤处钻至该水平面最有可能的深度是(&&&)A.25mB.45mC.55mD.65m
难易度:一般&&
更新时间: 18:42:44.0
【小题1】A【小题2】C【小题3】B解析:【小题1】图中河流所在位置为谷地;以河流为中心,向两翼岩层出现由老到新的变化,说明为背斜构造,即该地的地质地貌为背斜谷。故选A。【小题2】随着地壳抬升,流水下切侵蚀作用不断增强,河道加深;断续反复这种的过程就形成了河流阶地。据此推断,图中河流所在位置为下切最深的位置,说明形成年代最晚。故选C。【小题3】根据图中等高距可推知,②、⑤两地的相对高差介于0m到20m之间,且⑤处海拔较高。若在③处钻30m到达采集样本水平面,则在⑤处钻至该水平面最有可能的深度是30m到50m之间。故选B。
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就是手表的表盘上还有三个小表盘,这种手表可以当做计时秒表使用。指向10点位置的指针为时针,指向2点位置的指针为分针,这个和其他的手表一样。指向12点位置的红头秒针为计时秒针,这个秒针平时是静止的,按下计时装置后(就是2点位置的按钮)此秒针开始启动;12点位小表盘为30分钟累计计时,中心计时秒针每走一圈此针走一个小格,即1分钟;6点位小表盘为12小时累计计时,12点位的指针走一圈此针走一个小格,即0.5小时;当再次按下计时装置后(就是2点位置的按钮)后,上述三个表针(计时秒针、30分针累计、12小时累计)都将停止运转。当按下4点位的按钮后,上述三个表针(计时秒针、30分针累计、12小时累计)都将归零。9点位小表盘为秒针,和计时装置无关,无论计时装置是否启动,此针都在运转,每走一圈为1分钟(这种秒针一般叫小秒针,和中心秒针相区别)。3点位的表把和普通手表的表把没区别,为上弦和调整时间和日历所用。
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我们会通过消息、邮箱等方式尽快将举报结果通知您。Problem 17A
1) 38.7 cm 2) 58.5.cm 3) 1.15 m 4) -143 N 5) 3.50 x 10^-4 N6) 1.4 x 10^-3 N 7) 1.60 x 10^-19 C 8) 1.60 x 10^-19 C 9) 1.60 x 10^-19 C 10) 2.2 x 10^-17 C
Problem 17B
1) F(tot)=1.8 x 10^-10 N, 45? 2) 2.24 x 10^10 N pointing upward along the y-axis 3) F(tot)=1.74 x 10^-7 N, -21.22? 4) 3.84 x 10^-6 N directected along the -y axis 5) F(tot)=4.82 x 10^-19 N, 45? 6) F(tot)=4.53 x 10^-6 N, 26.6? 7) F(tot)=3.97 x 10^-8 N, 9.29? 8) F(x,tot)=7.2x10^4 N, F(y,tot)= -1.8 x 10^4 N, F(tot)=7.4 x 10^4 N, -14? 9) F(tot)=3.66 x 10^5 N, 45? 10) F(tot)=0 N along the x axis
Problem 17C
1) -1.7 x 10^-1 N 2) 18 N 3) 259 N 4) 16 cm 5) 36 cm 6) 7.3 cm
Problem 17D
1) -54 N in the -x direction 2) 7.5 x 10^-6 N in the +y direction 3) -3.29 x 10^-14 N upward 4) 4.40x10^5 N/C, 89.1? 5) 3.15 x 10^5 N/C 6) 5.06 x 10^-12 C 7) 1.61 x 10^-12 C 8) 3.6 x 10^-10 m 9) -0.67 mm 10) -1.37 x 10^-7 m
Section 17-1 Review, page 633
1) It is equal to the magnitude of the rod' Charge is conserved. 2) Charge is quantized. 3) 6.25 x 10^19 electrons 4) The taped induces a surface charge on the desk, so the two are attracted to one another. 6) More paint hits the object being painted because of an electrical attraction between the chargted droplets and the oppositely charged object.
Section 17-2 Review, page 642
1a) 4.4 N b) attractive c) 1.2 x 10^13 electrons 2) both are field forces, both are electric forces are attractive or repulssive whnile gravitational forces are always attractive, electric force is significantly stronger than gravitational force 3) 7.3 x 10^-8 N, along the negative x axis 4) 35.2 cm from q(1) (24.8 cm from q(2)) 5) new distance = 1/sqrt(2)(old distance)
Section 17-3 Review, page 652
1) 8.0 x 10^3 N/C, directed toward the 40.0 x 10^-9 C charge 2a) -3/8 b) q(1) q(2) is positive 3a) All lines should point away from the two charges, and one charge should have four time as many lines as the other. b) All lines should point toward the tow charges, and one charge should have four times as many lines as the other. 4) because charge accumulated at sharp points 5) They experience an electrical attraction that pulls them back toward the object.
Section 17-1 Worksheet
1a) Experiment A, no charges were transferred. Experiment B, charges were tranferred between the sphere and the ground. Experiment C, Charges were transferred between the sphere and the rod. b) Diagrams should show: Spher A, negative charges (-) on the left, positive (+) Sphere B, excess (-) Sphere C, excess (+) d) Experiment A e) no change in Experiment A or Experiment B; reduced charge in Experiment C
Section 17-2 Worksheet
1a) 20.0 cm b) 0.899 N (attraction along the line q(1)-q(3)) c) 0.899 N (attraction along the line q(1)-q(2)) d) 1.40 N repulsion pulling to the right e) Diagrams should show F(1) pointing from q(3) toward q(1) and F(2) pointing from q(3) toward q(2) f) 36.9? g) F(1x)=-0.709 N; F(2x)=0.719 N; F(1Y)=-0.540 N; F(2y)=-0.540 N h) -1.08 N pointing down i) downward along the y-axis
Section 17-3 Worksheet
1a) 21.2 cm b) all same strength of 1.60x10^-6 N/C along the diagonal lines, with E(1) pointing away from q(1), E(2) from q(2), E(3) from q(3), and E(4) from q(4) c) Resultant electric field E=0 2a) 4.61x10^-14 N down b) 4.61x10^-14 N up c) 1.44x10^-18 C d) 9 electrons

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