m^5+n^5进行降次，降职申请书怎么写写

来源：蜘蛛抓取(WebSpider) 时间：2015-04-12 05:49 标签： 降职申请书怎么写
m平方=m+1,n平方=n+1,且m不等于n ,求：m的7次方+n的7次方.请详细说明._百度作业帮
m平方=m+1,n平方=n+1,且m不等于n ,求：m的7次方+n的7次方.请详细说明.
m^2-m-1=0,n^2-n-1=0由题意知m,n为方程x^2-x-1=0的两个不同的实根.由韦达定理知m+n=1,mn=-1m^2+n^2+2mn=(m+n)^2m^2+n^2=1+2=3(m^2+n^2)^2=m^4+2(mn)^2+n^49=m^4+n^4+2m^4+n^4=7(m^2+n^2)(m+n)=m^3+mn^2+m^2n+n^33=m^3+n^3+mn(m+n)m^3+n^3=3-(-1)*1=4(m^3+n^3)(m^4+n^4)=m^7+n^7+m^3n^4+m^4n^3=m^7+n^7+m^3n^3(m+n)4*7=m^7+n^7+(-1)^3*1m^7+n^7=28-(-1)^3*1=28+1=29
X^2-X-1=0的两个根m+n=1mn=-11=(m+n)^2=m^2+n^2+2mn=m^2+n^2-2, m^2+n^2=31=(m+n)^3=m^3+n^3+3mn(m+n)=m^3+n^3-3m^3+n^3=4,
3x4=12=(m^2+n^2)(m^3+n^3)=m^5+n^5+(nm)^2(m+n)=m^5+n^...
将①m²=m＋1，②n²=n＋1不断代入原式进行降次化简：m﹙m²﹚³＋n﹙n²﹚³=m﹙m＋1﹚﹙m＋1﹚²＋n﹙n＋1﹚﹙n＋1﹚²=﹙2m＋1﹚﹙3m＋2﹚＋﹙2n＋1﹚﹙3n＋2﹚=13m＋8＋13n＋8=13﹙m＋n﹚＋16，由①－②=﹙m－n﹚﹙m＋n－1﹚=0，∵m≠n，∴m－n≠0，∴m＋n=1，代入化...
（m-1）平方=m+2（n-1）平方=n+2(1)-(2)m+n=3代入降次。
M^2=M+1则M^7=M(M+1)^3
=(M^2+M)(M+1)^2
=(M+1+M)(M^2+2M+1)
=(2M+1)(M+1+2M+1)
=(2M+1)(3M+2)
=6M^2+7M+2
=6(M+1)+7M+2
=13M+8同样N^...
m，n是方程X²-X-1的两个根X的7次方=X的6次方+X5次方=X5次方+X4次+X4次+X3次=3*X4次+2*X3次=5*X3次+3*X2次=8*X2次+5X=8(X+1)+5X=13X+8m的7次方=13m+8n的7次方=13n+8m的7次方+n的7次方=13*(m+n)+16=29若m^2=m+1,n^2=n+1,且m≠n,则m^5+n^5的值为_百度作业帮
若m^2=m+1,n^2=n+1,且m≠n,则m^5+n^5的值为
m^2=m+1,n^2=n+1.m^2-n^2=(m+1)-(n-1)(m+n)(m-n)=m-nm≠nm+n=1(m+n)^2=m^2+n^2+2mn=1m^2+n^2=(m+1)+(n+1)=m+n+2=1+2=32mn=1-(m^2+n^2)=1-3==-2mn=-1m^3+n^3=(m+n)(m^2+n^2-mn)=1*(3+1)=4(m^2+n^2)(m^3+n^3)=m^5+m^2n^3+n^2m^3+n^33*4=m^5+n^5+m^2n^2(m+n)m^5+n^5=12-(-1)^2*1=11您好 请问用含有字母的数字表示下面数量关系 m与n的和的3.5倍怎么写?_百度作业帮
您好 请问用含有字母的数字表示下面数量关系 m与n的和的3.5倍怎么写?
用关系式表示m与n的和的3.5倍 ：3.5X（m+n）our home., act together and clean up this city of ours..We need to h**e patrol police out on the street and issue on the spot fines for littering or any other indecent acts. 2. 3. We must h**e more ads **ut the importance of m**ing our cite cleaner as well as h**ing signs around the streets and on food packagings.. 5. We must **nd groups of cleaners out everyday to clean up our city. Most importantly, we must get up. We need to promote and e**cate our youngsters **ut the negative effects of littering in hope that they will help us in this process as well. 41
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若m2=m+1,n2=n+1,且m≠n,求m5+n5
答：m^2=m+1,m^2-m-1=0n^2=n+1,n^2-n-1=0所以：m和n都符合一元二次方程x^2-x-1=0所以：m、n是方程x^2-x-1=0的两个根
m^2-m-1=0,n^2-n-1=0m,n不是x^2-x-1=0的两根么。m^5+n^5（可以用降次的方法）=m^3m^2+n^3n^2=m^3(m+1)+n^3(n+1)=m4+m3+n4+n3=(m+1)2+m3+(N+1)2+n3m^2+2m+1+m(M+1)=2m^2+3m+1=2m+2+3m+1=5m+3同理得5n+3

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