10^(-1.8*y/10)*24=1.99 y=多少？？？求解

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AT24C08AY5-10YU-1.8 (ATMEL) PDF技术资料下载
AT24C08AY5-10YU-1.8 供应信息 IC Datasheet 数据表 (5/24 页)
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AT24C08AY5-10YU-1.8
2线串行EEPROM
[2-Wire Serial EEPROM]
&&AT24C08AY5-10YU-1.8PDF文件：
2线串行EEPROM[2-Wire Serial EEPROM]
文件大小：&&445 KPDF页数：
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&&&&ATMEL [ ATMEL CORPORATION ]
AT24C01A/02/04/08A/16ATable 5.AC CharacteristicsApplicable over recommended operating range from TAI=–40°C to +85°C, VCC= +1.8V to +5.5V, VCC= +2.7V to +5.5V,CL = 1 TTL Gate and 100 pF (unless otherwise noted)1.8-voltSymbolfSCLtLOWtHIGHtItAAtBUFtHD.STAtSU.STAtHD.DATtSU.DATtRtFtSU.STOtDHtWREndurance(1)Note:ParameterClock Frequency, SCLClock Pulse Width LowClock Pulse Width HighNoise Suppression Time(1)Clock Low to Data Out ValidTime the bus must be free beforea new transmission can start(1)Start Hold TimeStart Setup TimeData In Hold TimeData In Setup TimeInputs Rise Time(1)Inputs Fall Time(1)Stop Setup TimeData Out Hold TimeWrite Cycle Time5.0V, 25°C, Byte Mode1M4.710051M0.14.74.04.702001.03000.65054.74.01004.50.11.20.60.601000.3300MinMax1001.20.6500.92.7, 5.0-voltMinMax400UnitskHzususnsusususususnsusnsusnsmsWriteCycles1. This parameter is characterized.50180V–SEEPR–8/05扫二维码下载作业帮
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已知2x-y=10,求式子[(x^2+y^2)-(x-y)^2+2y(x-y)]/4y
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[(x^2+y^2)-(x-y)^2+2y(x-y)]/4y =[(x^2+y^2)-(x^2-2xy+y^2)+2xy-2y^2]/4y =[x^2+y^2-x^2+2xy-y^2+2xy-2y^2]/4y =(4xy-2y^2)/4y =2y(2x-y)/4y =(2x-y)/2=10/2=5
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其他类似问题
((x^2+y^2)-(x-y)^2+2y(x-y))/4y=(x^2+y^2-x^2-y^2+2xy+2xy-2y^2)/4y=(4xy-2y^2)/4y=x-y/2=(2x-y)/2=10/2=5
[(x²+y²)-(x-y)²+2y(x-y)]/4y=[2xy+2y(x-y)]/4y=(2x-y)/2=10/2=5
因为：2x-y=10[(x²+y²)-(x-y)²+2y(x-y)]/4y=[2xy+2y(x-y)]/4y=(2x-y)/2=10/2=5
[(x^2+y^2)-(x-y)^2+2y(x-y)]/4y=[x^2+y^2-x^2+2xy-y^2+2xy-2y^2]/4y=(4xy-2y^2)/4y=2y(2x-y)/4y=(2x-y)/2
(2x-y=10代入)=10/2=5
[(x²+y²)-(x-y)²+2y(x-y)]/4y=[2xy+2y(x-y)]/4y=(2x-y)/2=10/2=5
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